AP and TS EAMCET Engineering 2020 Model Paper 3

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Question : 80 of 160

Marks: +1, -0

∫

dx

(2x−7)√x2−7x+12

=

2sec−1(2x−7)+c
sec−1(2x−7)+c
1
2
sec−1(2x−7)+c
1
2
sec−1(2x+7)+c

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