AP and TS EAMCET Engineering 2020 Model Paper 3

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Question : 70 of 160

Marks: +1, -0

The solution of the differntial equation (1+y2)+(x−etan−1y)

dy

dx

=0 is

x−2=Ke−tan−1y
2xetan−1y=e2tan−1y+K
xetan−1y=tan−1y+K
xe2tan−1y=etan−1y+K

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