AP and TS EAMCET Engineering 2020 Model Paper 3

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Question : 14 of 160

Marks: +1, -0

If [

x	y2
2	0

]=[

1	8
2	0

] then [

x	y
2	0

]−1=

[
0 −2
−2 1
]
[
−1 3
2 −2
]
[
0 −8
−2 1
]
[
0
1
2
1
2
−
1
4
]

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