AP and TS EAMCET Engineering 2020 Model Paper 2

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Question : 54 of 160

Marks: +1, -0

The solution of the differential equation xy1=2xe−

y

x

+y is

ey∕x+log|cx|=0
e−y∕x=x+c
ey∕x=log|cx|
ey∕x=2‌log|cx|

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