AMU Engineering 2020 solved paper Solved Paper

NaCl solution in water gives H2 at cathode and Cl2 at anode because of low discharge potential of H+ions as compared to Na+ (at cathode) and of Cl−as compared to OH−ions (due to over voltage).
2H+

+2e−

⟶

H2(g)‌‌ (at cathode)
2Cl−

−2e−

⟶

Cl2(g) (at anode)