AMU Engineering 2020 solved paper Solved Paper

Let f be force of friction between the shell and horizontal surface
For translation motion we have, F+f=ma . . . (i)
For rotational motion,
FR−fR=Iα=I‌

a

R

‌‌[∴a=Rα‌ for pure rolling ‌]
⇒‌‌‌‌F−f=I‌

a

R2

‌‌...‌ (ii) ‌
On adding Eqs. (i) and (ii), we get
‌‌2F=(m+‌

I

R2

)a′=(m+‌

2

3

m)a=‌

5

3

ma
⇒‌‌F=‌

5

6

ma⇒a=‌

6F

5m