AMU Engineering 2020 solved paper Solved Paper

We know that capacitor offers infinite resistance for DC source (Battery is DC source).
Current taken from the cell.
I=‌

E

R+r

=‌

2.5

1+1+0.5

=1A
Potential drop across capacitance
V=E−Ir=2.5−1×0.5=2V
The current in 2Ωresistor is zero charge on capacitor Q=CV=5×2=10µC