AMU Engineering 2019 solved paper Solved Paper

Section: Mathematics

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Question : 144 of 150

Marks: +1, -0

If a is an arbitrary constant, then solution of the differential equation

dy

dx

+√

1−y2

1−x2

=0 is

x√1−y2+y√1−x2=a
y√1−y2+x√1−x2=a
x√1−y2−y√1−x2=a
y√1−y2−x√1−x2=a

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