© examsiri.com
Question : 139 of 150
Marks:
+1,
-0
Solution:
Given that
|a|=a Let
a=a1+a2+a3 ∴a2=a12+a22+a32 Now
×a=|| =−a3+a2 |×a|2=a32+a22 Similarly,
|×a|2=a12+a32 and
|×a|2=a12+a22 ∴
|×a|2+|×a|2+|×a|2 =a12+a22+a22+a32+a32+a12 =2(a12+a22+a32)=2a2
© examsiri.com
Go to Question: