AMU Engineering 2019 solved paper Solved Paper

Given that, equation of curves are
x=log(y+e) ......(i)
andy=log(

1

x

) .........(ii)
∴ From Eq. (i), we get
ex=(y+e) .........(iii)
Put the value of ' y ' from Eq. (ii) in Eq. (iii), we get
ex=log(

1

x

)+e=log‌x−1+e
=−log‌x+e
⇒log‌x=−ex+e⇒x=1∴y=0
∴ Point is (1,0)
∴ Curves meet at one point.