If \\theta=\sin ^{-1} x+\cos ^{-1} x-\tan ^{-1} x, x \\geq 0 then the smallest interval in which \\theta lies is

Correct Answer is : 0≤θ≤π4

\frac{\\pi}{2} \\leq \\theta \\leq \frac{3 \\pi}{4}

0 \\leq \\theta \\leq \frac{\\pi}{4}

-\frac{\\pi}{4} \\leq \\theta \\leq 0

\frac{\\pi}{4} \\leq \\theta \\leq \frac{\\pi}{2}

AMU Engineering 2019 solved paper Solved Paper

Section: Mathematics

Question : 122 of 150

Marks: +1, -0

If θ=sin−1x+cos−1x−tan−1x,x≥0 then the smallest interval in which θ lies is

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