AMU Engineering 2019 solved paper Solved Paper

n(S)=36
The probability of throwing 9 with two dice
{(3,6),(4,5),(5,4),(6,3)} =

4

36

=

1

9

∴ probability for not throwing 9=1−

1

9

=

8

9

∴ If A is to win, he should throw dice alternately (i.e., 1st,3rd and so on ) to get 9 and obviously for B is to win. He should throw dice in 2 nd, 4 th and so on.
∴ Probability that ' B ' wins
=(

8

9

)1.

1

9

+(

8

9

)3.

1

9

+.......
=

( 8 9 )× 1 9

1−( 8 9 )2

=

8

17