AMU Engineering 2018 solved paper Solved Paper

Given, mass of the ball, m=3kg,Δv=5m∕s and the time taken the man to throw a ball,
Δt=

2

4

=0.5s
∴ Change in momentum of the ball, Δp=m.Δv
=3×5=15N−s
Since, we know,
Force = Rate of change in linear momentum
F=

Δp

Δt

=

15

0.5

(Putting values)
=

15

5

×10=30N