AMU Engineering 2018 solved paper Solved Paper

Since, we know that from a position-time graph of a body.
Velocity of the body, v= slope of position-time graph.
From the graph,
v=

Δx

Δt

=

3

2

=

3

2

m∕s
Since, we know that
Impulse = Change in linear momentum
=m.v
4×

3

2

=6kg−ms−1