The intermediate product (X) formed in the following reaction is {B}_{2} {H}_{6}+6 {NH}_{3} \to3 X \stackrel{\text{Heat }{ ────▸} } 2 {B}_{3} {N}_{3} {H}_{6} +12 {H}_{2}

Correct Answer is : [BH2(NH3)2]+[BH4]−

[{BH}({NH}_{3})_{3}]^{+}[{BH}_{4}]^{-}

[{BH}_{2}({NH}_{3})_{4}]^{+}[{BH}_{4}]^{-}

[{BH}({NH}_{3})_{4}]^{+}[{BH}_{4}]^{-}

[{BH}_{2}({NH}_{3})_{2}]^{+}[{BH}_{4}]^{-}

AMU Engineering 2018 solved paper Solved Paper

Section: Chemistry

Question : 63 of 150

Marks: +1, -0

The intermediate product (X) formed in the following reaction is
B2H6+6NH3→3X

Heat

────▸

2B3N3H6 +12H2

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