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Question : 144 of 150
Marks:
+1,
-0
Solution:
Let
P(3λ+2,4λ−1,12λ+2) be any point lie on line
== Since, line intersect the plane
x−y+z=5 ∴P(3λ+2,4λ−1,12λ+2) lie on plane
| ∴3λ+2−(4λ−1)+12λ+2=5 |
⇒11λ+5=5 ⇒λ=0 ∴P(2,−1,2) Distance from
(1,−2,3) and
(2,−1,2) is
√(2−1)2+(−1+2)2+(2−3)2 =√1+1+1=√3
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