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Question : 127 of 150
Marks:
+1,
-0
Solution:
We have,
y=a‌cos(log‌x)+b‌sin(log‌x) On differentiating both sides w.r.t.
x, we get
=−+ ⇒x=−a‌sin(log‌x)+b‌cos(log‌x) Again differentiating w.r.t
x, we get
x+=− − ⇒x2+=−(a‌cos(log‌x) +b‌sin(log‌x)) ⇒x2+x+y=0
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