AMU Engineering 2018 solved paper Solved Paper

A number is divisible by b if sum of its digit is divisible by 3. Now, out of 0,1,2,3,4,5 if we take 1,2,3,4,5 or 0,1,2,4,5. Then, 5 -digit number will be divisible by 3.
Case I Total number of five-digit number formed using the digits 1,2,3,4,5 is 5!=120
Case II Taking 0,1,2,4,5
Total number is 4×4!=4×24=96
Hence, total number divisible by 3 is 120+96=216
Note There is a correction in question. The five-digit number is formed using 0,1,2,3,4,5