AMU Engineering 2018 solved paper Solved Paper

Given, A family has 3 children.
∴ Sample space ={BBB,BBG,BGB,GBB,GGG,GGB, GBG,BGG}
A is the event that family has children of both sexes.
∴A={BBG,BGB,GBB,GGB, GBG,BGG}
B be the event that family has atmost one boy.
∴B={GGG,GGB,GBG,BGG}
A∩B={GGB,GBG,BGG}
P(A)=

6

8

,P(B)=

4

8

,P(A∩B)=

3

8

P(A)×P(B)=

6

8

×

4

8

=

3

8

=P(A∩B)
∴A and B are independent events.