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Question : 116 of 150
Marks:
+1,
-0
Solution:
We have,
a1,a2,a3,a4,.......,an are in AP.
We know that, if
a1,a2,a3........an in AP, then
a1+an=a2+an−1=a3+an−2 =........=ar+an−(r−1) Now,
+++......+ =[++...... +] =[+ +.....+] =[1an++++...... ++] =[++ +........+] =[+++......... +] ∴K=2
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