For the reaction, S_{(\text{rhombic })}+{O}_{2} \\to{SO}_{2}, \\DeltaH=-298 {kJ} {mol}^{-1} at 25^\circ{C} and {l} atm. Therefore, \\DeltaE for the reaction should be

Correct Answer is : −298kJmol−1

-298+8.314 \\times298 {kJ} {mol}^{-1}

-298-8.314 \\times29{kJ} {mol}^{-1}

-298-2 \\times8.314 \\times298 {kJ} {mol}^{-1}

AMU Engineering 2017 solved paper Solved Paper

Section: Chemistry

Question : 94 of 150

Marks: +1, -0

For the reaction, S(rhombic )+O2→SO2, ΔH=−298kJmol−1 at 25°C and l atm.
Therefore, ΔE for the reaction should be

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