AMU Engineering 2017 solved paper Solved Paper

Equivalent resistance and current in the circuit has been calculated in the figures given below In series, Req=1+1=2Ω
Inparallel, Req=2×22+2=1Ω In series Req=2+1=3Ω In series, Req =

6×3

6+3

=2Ω In series, Req=2+2=4Ω ∴emf,E=( Total current )×( Net equivalentresistance)
=3×4=12V