For the reaction : {\X}_2 {\O}_4(ℓ) \rightarrow 2 {\XO}_2( {\g}) ∆ {\U}=2.1 {\k} {\cal}, ∆ {\S}=20 {\cal} {\K}-1 at 300 {\K} Hence ∆ G is :-

AIPMT 2014 Physics and Chemistry Paper

Question : 58 of 90

Marks: +1, -0

For the reaction :
X2O4(ℓ)⟶2XO2(g)
∆U=2.1k‌cal,∆S=20‌cal‌K−1 at 300K
Hence ∆G is :-

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