Steam at 100^{\circ} {\C} is passed into 20 {\g} of water at 10^{\circ} {\C}. When water acquires a temperature of 80^{\circ} {\C}, the mass of water present will be : [Take specific heat of water =1 {\cal} {\g}^{-1}{ }^{\circ} {\C}^{-1} and latent heat of steam =540 {\cal} {\g}^{-1} ]

AIPMT 2014 Physics and Chemistry Paper

Question : 15 of 90

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Steam at 100∘C is passed into 20g of water at 10∘C. When water acquires a temperature of 80∘C, the mass of water present will be :
[Take specific heat of water =1‌cal‌g−1‌‌∘‌C−1 and latent heat of steam =540‌cal‌g−1 ]

249
31.5g
42.5g
22.5g

Validate

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