AIPMT 2013 Physics and Chemistry Paper

Magnetic moment 1.73‌BM
µ=√n(n+2) B.M
n= no. of unpaired e−
µ=1.73
1.73=√n(n+2) B.M
n=1
● [CoCl6]4−‌‌→‌‌Co+2;d7
Cl−(weak field ligand) t2g5eg2 unpaired e−=3
● [Cu(NH3)4]2+Cu+2−d9
NH3 Strong field ligand, hybridisation dsp ‌2
● one e−of 3d jumps into 4p subshell.
unpaired e−=1
● [Ni(CN)4]2−‌‌→Ni+2−d8 unpaired e−=0
CN−−Strong field ligand dsp2
●TiCl4→Ti+4d∘ unpaired e−=zero .