The instantaneous angular position of a point on a rotating wheel is given by the equation \theta(t)=2 t^3-6 t^2. The torque on the wheel becomes zero at :

AIPMT 2011 Physics and Chemistry Solved Paper

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The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t)=2t3−6t2. The torque on the wheel becomes zero at :

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