{\H}_3 {\C}- {\C_{|↙{ \CH_3}}H}- {\CH}= {\CH}_2+ {\HBr} \rightarrow(X) Here ( {\X}) (predominantly) is :

Correct Answer is : CH3−Br|C|CH3−CH2CH3

{\CH}_3- {\C_{|↙{ \Br}}H}- {\C_{|↙{ \CH_3}}H}- {\CH}_3

{\CH}_3- {\C_{|↙{ \CH_3}}H}- {\C_{|↙{ \Br}}H}- {\CH}_3

{\CH}_3- {\C_{|↙{ \CH_3}}H}- {\CH}_2- {\CH}_2 {\Br}

{\CH}_3- {\C^{|↖{ \Br}}_{|↙{ \CH_3}}}- {\CH}_2 {\CH}_3

AIPMT 2008 Physics and Chemistry Paper

Question : 90 of 100

Marks: +1, -0

H3C−

‌‌‌‌‌CH3

H−CH=CH2+HBr⟶(X) Here (X) (predominantly) is :

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