On the basis of the following E^{\circ} values, the strongest oxidizing agent is : [ {\Fe}( {\CN})_6]^{4-} \to[ {\Fe}( {\CN})_6]^{3-}+ {\e}^{-1}, {\E}^0=-0.35 {\V} {\Fe}^{2+} \to {\Fe}^{3+}+ {\e}^{-1}, {\E}^{\circ}=-0.77 {\V}

Correct Answer is : [Fe(CN)6]3−

AIPMT 2008 Physics and Chemistry Paper

Question : 65 of 100

Marks: +1, -0

On the basis of the following E∘ values, the strongest oxidizing agent is :
[Fe(CN)6]4−→[Fe(CN)6]3−+e−1,E0=−0.35V
Fe2+→Fe3++e−1,E∘=−0.77V

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