Consider the reaction {\N}_2( {\g})+3 {\H}_2( {\g}) \to 2 {\NH}_3( {\g}) The equality relationship between { {\d}[ {\NH}_3]}/{ {\dt}} and - { {\d}[ {\H}_2]}/{ {\dt}} is :-

Correct Answer is : +d[NH3]dt=−23d[H2]dt

{ {\d}[ {\NH}_3]}/{ {\dt}}=-\frac{1}{3} { {\d}[ {\H}_2]}/{ {\dt}}

+ { {\d}[ {\NH}_3]}/{ {\dt}}=-\frac{2}{3} { {\d}[ {\H}_2]}/{ {\dt}}

+ { {\d}[ {\NH}_3]}/{ {\dt}}=-\frac{3}{2} { {\d}[ {\H}_2]}/{ {\dt}}

{ {\d}[ {\NH}_3]}/{ {\dt}}=- { {\d}[ {\H}_2]}/{ {\dt}}

AIPMT 2006 Physics and Chemistry Paper

Question : 77 of 100

Marks: +1, -0

Consider the reaction N2(g)+3H2(g)→2NH3(g)
The equality relationship between ‌

d[NH3]

and −‌

d[H2]

is :-

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