If the bond energies of {\H}- {\H}, {\Br}- {\Br} and {\H}- {\Br} are 433,192 and 364 {\kJ} {\mol}^{-1} respectively the ∆ {\H}^{\circ} for the reaction {\H}_2( {\g})+ {\Br}_2( {\g}) \to 2 {\HBr}( {\g}) is-

AIPMT 2004 Physics and Chemistry Paper

Question : 59 of 100

Marks: +1, -0

If the bond energies of H−H,Br−Br and H−Br are 433,192 and 364‌kJ‌mol−1 respectively the ∆H∘ for the reaction H2(g)+Br2(g)→2‌HBr(g) is-

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