The phase difference between two waves, represented by y_1=10^{-6} \sin \{100 {\t}+( {\x} \/ 50)+0.5\} {\m} {\y}_2=10^{-6} \cos \{100 {\t}+ (\frac{ {\x}}{50}) \} {\m} Where X is expressed in metres and t is expressed in seconds, is approximately : -

Correct Answer is : 1.07 radians

AIPMT 2004 Physics and Chemistry Paper

Question : 33 of 100

Marks: +1, -0

The phase difference between two waves, represented by
‌y1=10−6sin‌{100t+(x∕50)+0.5}m
‌y2=10−6‌cos{100t+(‌

)}‌m
Where X is expressed in metres and t is expressed in seconds, is approximately : -

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