The compound \CH_3-\C↖\stackrel{\CH_3}{|}= \CH-\CH_3 on reaction with {\NaIO}_4 in the presence of {\KMnO}_4 given :

Correct Answer is : CH3COCH3+CH3COOH

{\CH}_3 {\COCH}_3+ {\CH}_3 {\COOH}

{\CH}_3 {\COCH}_3+ {\CH}_3 {\CHO}

AIPMT 2003 Physics and Chemistry Paper

Question : 78 of 100

Marks: +1, -0

The compound CH3−

CH3

=CH−CH3 on reaction with NaIO4 in the presence of KMnO4 given :

Go to Question:

Prev Question

Next Question