The solubility product of AgI at 25^{\circ} {\C} is 1.0 \times 10^{-16} {\mol}^2 {\L}^{-2}. The solubility of {\AgI} in 10^{-} { }^4 {\N} solution of {\KI} at 25^{\circ} {\C} is approximately (in {\mol} {\L}^{-1}) :

Correct Answer is : 1.0×10−12

AIPMT 2003 Physics and Chemistry Paper

Question : 67 of 100

Marks: +1, -0

The solubility product of AgI at 25∘C is 1.0×10−16mol2L−2. The solubility of AgI in 10− ‌4N solution of KI at 25∘C is approximately (in mol‌L−1) :

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