Stand electrode potential are \Fe^{+2}\/\Fe \E^\circ=-0.44 \Fe^{+3}\/\Fe^{+2} \E^\circ=0.77 If \Fe^{+2}, \Fe^{+3} and Fe block re kept together, then

Correct Answer is : Fe+3 decreases

{\Fe^{+2}}/{\Fe^{+3}} remains unchanged

AIPMT 2001 Physics and Chemistry Paper

Question : 78 of 100

Marks: +1, -0

Stand electrode potential are
Fe+2∕Fe‌‌‌E°=−0.44
Fe+3∕Fe+2‌‌‌E°=0.77
If Fe+2,Fe+3 and Fe block re kept together, then

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