The conductivity of a 0.05 M solution of a weak monobasic acid is 10^{–3}5cm^{–1}. If \lambda^{\infty}_m for weak acid is 500 5cm^2\mol^{–1}, calculate Ka of weak monobasic acid :

AIIMS 26 May 2019 Evening Question Paper with solutions for online practice

Question : 68 of 123

Marks: +1, -0

The conductivity of a 0.05 M solution of a weak monobasic acid is 10–35cm–1. If λm∞ for weak acid is 500‌5cm2mol–1, calculate Ka of weak monobasic acid :

8×10–5
4×10–6
16×10–7
14×10–8

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