AIIMS 2018 May 26 Chemistry Evening Question Paper with solutions for online practice

Oxidation state of Cr in [Cr(H2O6)]+2 is +2
Electronic configuration of Cr=(Ar)184S13d5
Electronic configuration of Cr2+=(Ar)163d4
H2O is W & F ligand
CFSE value =[−0.4n2g+0.6neg]Δ0+nP
=[−0.4×3+0.6×1]Δ0+0
=−0.6Δ0
Oxidation state of Cr in [Cr(H2O)6]+3 is +3
Electronic configuration of Cr3+=(Ar)183d3
CFSE value =[−0.4n+2g+0.6neg]Δ0+nP
=[−0.4×3+0]Δ0+0
=−1.2Δ0
CFSE does not effect colour rather 0 value can change colour.