A point particle of mass 0.1 kg is executing S.H.M. of amplitude of 0.1 m. When the particle passes through the mean position, its kinetic energy is 8 \times 10^{-3} Joule. Obtain the equation of motion of this particle if this initial phase of oscillation is 45°.

Correct Answer is : y=0.1sin(±4t+π4)

AIIMS 2017 Physics Question Paper for free online practice with solutions

Question : 16 of 60

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A point particle of mass 0.1 kg is executing S.H.M. of amplitude of 0.1 m. When the particle passes through the mean position, its kinetic energy is 8×10−3 Joule. Obtain the equation of motion of this particle if this initial phase of oscillation is 45°.

y=0.1sin(±4t+
π
4
)
y=0.2sin(±4t+
π
4
)
y=0.1sin(±2t+
π
4
)
y=0.2sin(±2t+
π
4
)

Validate

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