AIIMS 2015 Chemistry Question Paper for free online practice with solutions

© examsiri.com
Question : 36 of 60
 
Marks: +1, -0
Formation of polyethylene from calcium carbide takes place is follows:
CaC2+2H2O→Ca(OH)2+C2H2
C2H2+H2→C2H4
nC2H4→−(CH2−CH2)−n
The amount of polyethylene obtained from 64.0 kg of CaC2 is
Go to Question: