AIEEE 2012 Solved Paper

Section: Mathematics

Question : 86 of 89

Marks: +1, -0

Consider the function, f(x)=|x−2|+|x−5|,x∈R
Statement - 1:f′(4)=0
Statement −2:f is continuous in [2,5], differentiable in (2,5) and f(2)=f(5)

[AIEEE 2012]

Statement −1 is false, statement - 2 is true
Statement −1 is true, statement −2 is true; statement - 2 is a correct explanation for statement - 1
Statement −1 is true, statement - 2 is true; statement −2 is not a correct explanation for statement - 1
Statement −1 is true, statement −2 is false

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x−2,	x−2≥0
2−x,	‌x−2≤0

x−2,	x≥2
2−x,	x≤2

x−5,	‌x≥5
5−x,	‌x≤5