Ionisation energy of {\He}^{+}is 19.6 \times 10^{-18} {\J}^{\text{atom}}{ }^{-1}. The energy of the first stationary state ( {\n}= 1) of {\Li}^{2+} is [AIEEE 2010]

Correct Answer is : −4.41×10−17 J atom−1

4.41 \times 10^{-16} J atom ^{-1}

-4.41 \times 10^{-17} J atom^{-1}

-2.2 \times 10^{-15} J atom ^{-1}

8.82 \times 10^{-17} J atom^{-1}

AIEEE 2010 Solved Paper

Section: Chemistry

Question : 2 of 89

Marks: +1, -0

Ionisation energy of He+is 19.6×10−18J‌atom‌‌−1. The energy of the first stationary state (n= 1) of Li2+ is

[AIEEE 2010]

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