Statement-1: ∼(p \leftrightarrow ∼ q) is equivalent to p \leftrightarrow q. Statement-2: ∼(p \leftrightarrow ∼ q) is a tautology. [AIEEE 2009]

Correct Answer is : Statement- 1 is true, Statement- 2 is false

Statement- 1 is true, Statement- 2 is true; Statement- 2 is a correct explanation for Statement-1

Statement- 1 is true, Statement- 2 is true; Statement- 2 is not a correct explanation for Statement-1

Statement- 1 is true, Statement- 2 is false

Statement- 1 is false, Statement-2 is true

AIEEE 2009 Solved Paper

Section: Mathematics

Question : 87 of 89

Marks: +1, -0

Statement-1: ∼(p↔∼q) is equivalent to p↔q.
Statement-2: ∼(p↔∼q) is a tautology.

[AIEEE 2009]

Statement- 1 is true, Statement- 2 is true; Statement- 2 is a correct explanation for Statement-1
Statement- 1 is true, Statement- 2 is true; Statement- 2 is not a correct explanation for Statement-1
Statement- 1 is true, Statement- 2 is false
Statement- 1 is false, Statement-2 is true

p	q	p↔q	∼q	p↔∼q	∼(p↔∼q)
T	T	T	F	F	T
T	F	F	T	T	F
F	T	F	F	T	F
F	F	T	T	F	T

Go to Question:

Prev Question

Next Question