In Cannizzaro reaction given below 2 {\PhCHO} \stackrel{:{\OH}{────▶}^{(-) }} {\PhCH}_2 {\OH}+ \stackrel{..}{\PhC{\O_2}}{ }^{(-)} the slowest step is : [AIEEE 2009]

Correct Answer is : the transfer of hydride to the carbonyl group

the transfer of hydride to the carbonyl group

the abstraction of proton from the carboxylic group

the attack of : \stackrel{(-)}{O H} at the carboxyl group

the deprotonation of {\Ph} {\CH}_2 {\OH}

AIEEE 2009 Solved Paper

Section: Chemistry

Question : 25 of 89

Marks: +1, -0

In Cannizzaro reaction given below 2‌PhCHO‌

(−)

────▶

‌PhCH2‌OH+PhC‌

‌‌(−) the slowest step is :

[AIEEE 2009]

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