AIEEE 2008 Solved Paper

Number of electron in NO+=number of electron in CN−=14 electrons.
As both have same number of electrons so their bond order is equal.
Moleculer orbital configuration of NO+(14 electrons) is
∴B.0=‌

1

2

[10−4]=3
Moleculer orbital configuration of CN−(14 electrons) is
=σ1s2σ1s2*σ2s2σ2s2*π2px2=π2py2σ2pz2
∴B.0=‌

1

2

[10−4]=3