A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that A B(=a) subtends an angle of 60^{\circ} at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30^{\circ}. The height of the tower is [AIEEE 2007]

AIEEE 2007 Solved Paper

Section: Mathematics

Question : 95 of 118

Marks: +1, -0

A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB(=a) subtends an angle of 60∘ at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30∘. The height of the tower is

[AIEEE 2007]

a/√3
a√3
2a/√3
2a√3

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