A charged particle with charge q enters a region of constant, uniform and mutually orthogonal fields \overrightarrow{E} and \overrightarrow{B} with a velocity \overrightarrow{v} perpendicular to both \overrightarrow{E} and \overrightarrow{B}, and comes out without any change in magnitude or direction of \overrightarrow{v}. Then [AIEEE 2007]

Correct Answer is : →v=→E×→B/B2

\overrightarrow{v}=\overrightarrow{B} \times \overrightarrow{E} {/} E^2

\overrightarrow{v}=\overrightarrow{E} \times \overrightarrow{B}{/} B^2

\overrightarrow{v}=\overrightarrow{B} \times \overrightarrow{E} {/}B^2

\overrightarrow{v}=\overrightarrow{E} \times \overrightarrow{B} {/}E^2

AIEEE 2007 Solved Paper

Section: Physics

Question : 65 of 118

Marks: +1, -0

A charged particle with charge q enters a region of constant, uniform and mutually orthogonal fields

→

and

→

with a velocity

→

perpendicular to both

→

and

→

, and comes out without any change in magnitude or direction of

→

. Then

[AIEEE 2007]

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