A point mass oscillates along the x-axis according to the law x=x_0 \cos (\omega t-\pi \/ 4). If the acceleration of the particle is written as a=A \cos (\omega t+\delta), then [AIEEE 2007]

Correct Answer is : A=x0ω2,δ=3π/4

A=x_0 \omega^2, \delta=3 \pi {/} 4

A=x_0 \omega^2, \delta=\pi {/} 4

A=x_0 \omega^2, \delta=-\pi {/} 4

AIEEE 2007 Solved Paper

Section: Physics

Question : 55 of 118

Marks: +1, -0

A point mass oscillates along the x-axis according to the law x=x0‌cos(ωt−π∕4). If the acceleration of the particle is written as a=A‌cos(ωt+δ), then

[AIEEE 2007]

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