The potential energy of a 1 {\kg} particle free to move along the x-axis is given by V(x)= (\frac{x^4}{4}-\frac{x^2}{2}) J The total mechanical energy of the particle is 2 J. Then, the maximum speed (in {\m} \/ { s} ) is [AIEEE 2006]

AIEEE 2006 Solved Paper

Section: Physics

Question : 62 of 143

Marks: +1, -0

The potential energy of a 1‌kg particle free to move along the x-axis is given by V(x)=(‌

−‌

)J
The total mechanical energy of the particle is 2J. Then, the maximum speed (in m∕ s ) is

[AIEEE 2006]

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