AIEEE 2005 Physics Solved Paper

Section: Physics

Question : 2 of 74

Marks: +1, -0

A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate ‌

to come to rest. If the total distance traversed is 15S, then

[AIEEE 2005]

S=‌
1
6
ft2
S=ft
S=‌
1
4
ft2
S=‌
1
72
ft2

Validate

Go to Question:

Prev Question

Next Question