AIEEE 2004 Physics Solved Paper

We know that equation of motion, s=ut+‌

1

2

gt2,
Initial speed of ball is zero and it take T second to reach the ground.
∴h=‌

1

2

gT2
After T/3 second, vertical distance moved by the ball
h′=‌

1

2

g(‌

T

3

)2
⇒h′=‌

1

2

×‌

8T2

9

=‌

h

9

∴ Height from ground
=h−‌

h

9

=‌

8h

9