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AIEEE 2004 Math Solved Paper

Section: Mathematics
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Question : 45 of 68
 
Marks: +1, -0
If f(x)=‌
ex
1+ez
,I1=
f(a)
∫
f(−a)
xg{x(1−x)}‌dx and I2=
f(a)
∫
f(−a)
g{x(1−x)}‌dx, then the value of ‌
I2
I1
 is
[AIEEE 2004]
Validate
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